ShmoopTube

Where Monty Python meets your 10th grade teacher.

Search Thousands of Shmoop Videos

ACT Math 5.3 Pre-Algebra 435 Views


Share It!


Description:

ACT Math: Pre-Algebra Drill 5, Problem 3. Find the remainder.

Language:
English Language

Transcript

00:03

Here's an unshmoopy question you'll find on an exam somewhere in life.

00:07

If n is divisible by both 2 and 5, what is the remainder when n + 2 is divided by 4?

00:14

And here are the potential answers.

00:20

So, this question is asking us about remainders,

00:22

or what's left over when we divide one number by another.

00:26

Something neat we can do with remainders is that, if n is divisible by 2 and 5, we just

00:32

multiply 2 and 5... and we know that n is also divisible by 10.

00:37

Therefore, we know that n could be 10, 20, 30, 40, etc.

00:41

and n + 2 could be 12, 22, 32, 42...

00:46

The question asks us what the remainder is when n + 2 is divided by 4

00:52

so if we just test the possible n + 2 numbers

00:56

then 12 divided by 4 gives us 3 with a remainder of 0.

01:00

22 divided by 4 gives us 5 with a remainder of 2.

01:04

32 divided by 4 gives us 8 with a remainder of 0.

01:08

42 divided by 4 gives us 10 with a remainder of 2.

01:12

Looks like the remainder when n + 2 is divided by 4 is either 0 or 2.

01:19

Our answer is E.

01:21

As in, Egg salad sandwich.

Up Next

ACT Math 3.1 Plane Geometry
2559 Views

ACT Math: Plane Geometry Drill 3, Problem 1. What is the area of the trapezoid shape in the video?

Related Videos

Inequalities in Number Lines
3230 Views

ACT Math: Coordinate Geometry Drill 1, Problem 1. Which inequality is expressed by the number line?

ACT Math 3.1 Intermediate Algebra
1955 Views

ACT Math: Intermediate Algebra: Drill 3, Problem 1. Find the fifth number in the series.

Simplifying Radicals
9741 Views

We don't like knocking people down to size, but we do like simplifying radicals. Join us?

Arithmetic Math
2251 Views

If fleeing criminals always fled the scene of the crime at perfect right angles, it would be much easier to determine their whereabouts. Fortunatel...