ShmoopTube

Where Monty Python meets your 10th grade teacher.

Search Thousands of Shmoop Videos

ACT Math 6.5 Pre-Algebra 285 Views


Share It!


Description:

ACT Math: Pre-Algebra Drill 6, Problem 5. If one more data value of 55 is added to the data set, which values will change?

Language:
English Language

Transcript

00:03

Here's your shmoop du jour:

00:05

If one more data value of 55 is added to the

00:07

below data set, which values will change?

00:12

And here are the potential answers...

00:16

OK so what is this question asking?

00:18

Well, if we solved the previous problem, we know that the mean

00:22

of the original data set is 54...

00:25

...and the median and mode are both 55.

00:28

Okay, so the new 55 is going to stir the pot a bit.

00:31

But before we spend a ton of time doing a bunch more math, let's look at this logically.

00:35

Our median, the middle number... won't change.

00:38

55 was our median before, and since we're adding another one... it'll still be 55.

00:43

Same thing with mode. We already had more 55's than any other number... so adding

00:48

one more to the mix certainly won't change things.

00:51

Our mean was 54 in the last problem... by adding a 55, our mean is destined to go up

00:56

slightly...

00:58

So our answer is A.

00:59

As in, "All wet."

Up Next

ACT Math 3.1 Plane Geometry
2559 Views

ACT Math: Plane Geometry Drill 3, Problem 1. What is the area of the trapezoid shape in the video?

Related Videos

Inequalities in Number Lines
3235 Views

ACT Math: Coordinate Geometry Drill 1, Problem 1. Which inequality is expressed by the number line?

ACT Math 3.1 Intermediate Algebra
1956 Views

ACT Math: Intermediate Algebra: Drill 3, Problem 1. Find the fifth number in the series.

SAT Math 6.1 Geometry and Measurement
3974 Views

SAT Math 6.1 Geometry and Measurement

CAHSEE Math 3.4 Statistics, Data, and Probability I
363 Views

Statistics, Data, and Probability I: Drill Set 3, Problem 4. How many different avatars can be created based on the given options?