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TSI Math: Using Intercepts to Find the Slope of a Line 5 Views


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Description:

Line A has an x-intercept of -4 and a y-intercept of 8. What is its slope?


Transcript

00:02

Yes i'm ass shmoop er's here Another one for you

00:04

here's question line has an x intercept of negative for

00:08

an a y intercept of eight What is it's slow

00:16

Okay so time to rise up and run to the

00:19

solution way Have a slope to calculate All right Given

00:23

two points the slope is the difference of the y

00:25

co ordinates divided by the difference of the x coordinates

00:29

Right The rise over the run or the y two

00:31

minus y wan over x to minus x one Okay

00:34

one problem though we don't have the coordinates yet finer

00:37

detail but we kind of do They're being sneaky and

00:39

x intercept is located on the x axis It intercepts

00:44

the x axis right there So it must have a

00:47

y coordinate of zero right it's going nowhere just inside

00:50

of that thing So x intercept of negative four has

00:53

the coordinates Negative for and then zero because the y

00:56

thing use zero similarly Ah why Intercept is located on

01:00

the y axis which means it is an x coordinate

01:03

of zero for second point zero come eight We'll plug

01:06

these coordinates into the slope equation there like this And

01:09

we got eight month zero over zero minus negative for

01:12

yes that's tricky So it's eight over four We simplify

01:15

it and line a has a slope of to for 00:01:18.488 --> [endTime] the answers as in we're done

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