Multiplication Property
As long as both and
exist,
In words, the limit of a product is the product of the limits, as long as the limits involved exist.
Here's a few more examples of this:
- Assume
Then - Assume
Then - Assume
Then
Sample Problem
Find
If we try to break this limit into pieces, we find
This is trouble, because
What do we find if we multiply ∞ by something (if we could do such a thing, which we can't because ∞ is not a number)? It would make reasonable sense to assume we'd get ∞ again.
What do we get if we multiply a number by 0? We get 0. What if we try to multiply ∞ by 0? That makes no sense at all.
It turns out that in this case we can't find the limit of the product via the product of the limits.
However, we can still find the original limit we were asked about.
Since
Division Property
If the limits of f and g exist and
,
then
Suppose and
Then,
If , we can't use the rule we've been using to evaluate something like
.
If we try we find that
then we're out of luck.
Example 1
If
what is
|
Example 2
Assume that What is |
Example 3
Assume that What is |
Example 4
Assume that What is |
Exercise 1
Find the following limit, assuming that and
.
Exercise 2
Find the following limit, assuming that and
.
Exercise 3
Find the following limit, assuming that and
.
Exercise 4
Find the following limit, assuming that and
.
Exercise 5
Find the following limit, assuming that and
.
Exercise 6
Assuming that and
,find the following limit.
Exercise 7
Assuming that and
, find the following limit.
Exercise 8
Assuming that and
,find the following limit.
Exercise 9
Assuming that and
,find the following limit.
Exercise 10
Assuming that and
,find the following limit.
Exercise 11
Find (we may assume this limit exists), given that
.
Exercise 12
Find (we may assume this limit exists), given that
.
Exercise 13
Find (we may assume this limit exists), given that
Exercise 14
Find (we may assume this limit exists), given that
.
Exercise 15
Find (we may assume this limit exists), given that
.