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Algebra I Drill 2, Problem 3. Which of the following is the same as the expression?
SAT Math 1.1 Algebra and Functions 315 Views
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Description:
SAT Math 1.1 Algebra and Functions. Find an algebraic equation to correspond with the data.
Transcript
- 00:02
And we're getting mathy with it.
- 00:04
The table below gives the average maximum heart rate, by age, for a person exercising at full effort.
- 00:10
(Heart rate is in beats/min.)
- 00:13
Find an algebraic equation to correspond with the data.
- 00:16
Use a for age and h for heart rate.
Full Transcript
- 00:19
And here are your possible answers...
- 00:23
Okay, if we look at the data…
- 00:25
as age increases by 5, average max heart rate decreases by 5.
- 00:31
Since age acts as our independent variable and average max heart rate acts as our dependent variable,
- 00:42
we can calculate the change in average heart rate over age as the slope of our equation.
- 00:48
Which gives us negative 1. That's the slope.
- 00:51
The point slope form of a linear equation is y minus y1 equals slope times x minus x1.
- 00:58
And you should get that there are 2 points we’re thinking through here…
- 01:01
...that’s (x, y) and (x1, y1). h is y in this situation because it's the
- 01:06
dependent variable, and a is x in this situation because it's the independent variable.
- 01:12
We can take any x1 and y1 points... so let's just take the points 20 and 200.
- 01:18
Plugging into the equation with these numbers then, we get... h - 200 = -1(a - 20).
- 01:25
h minus 200 equals negative a plus 20.
- 01:28
Adding 220 to both sides of the equation... we have h equals 220 minus a.
- 01:34
Let's make sure this equation checks out with the data in the table....
- 01:37
Let’s plug in age 45 and see if the end answer is right.
- 01:42
Plugging in a equals 45...
- 01:44
h = 220 - 45, so that's 175.
- 01:49
Check it here on the table and yup, it checks out!
- 01:51
So our equation is h equals 220 minus a.
- 01:56
Answer A is our guy!
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