Combining the derivatives of basic functions with the chain rule gives us a lot of patterns that let us take derivatives of functions that seem complicated.
Sample Problem
Let h(x) = ecos x. If we think of this as h(x) = f(g(x)) where f(□) = e□ and g(x) = cos x,
the chain rule tells us that
h'(x) = f ' (g(x)) · g ' (x)
= ecos x · (cos x)'
= ecos x · (-sin x)
If instead we use Leibniz notation, we have z = ey where y = cos x. The chain rule says
.
Thankfully, we find the same thing either way: the derivative is the original function ecos x, multiplied by the derivative of the power.
We can state this formally as
(eu)' = eu · u',
assuming that the prime notation means "take the derivative with respect to x." Using Leibniz notation, we would say
There's also a less formal way that might make more sense:
if h(x) = e{□}, then the derivative of h is
h ' (x) = e{□} × (□)'
Similarly, the chain rule tells us that
and so on and so forth. These are good patterns to know, because then we can find derivatives without having to think much about the chain rule.
Exercise 1
What is the derivative of ex3 + 2x?
Exercise 2
What's the derivative of the following expression?
- cos(x5)
Exercise 3
Find the derivative of the expression.
- (cos x)5
Exercise 4
What's the derivative of the following expression?
- esin x
Exercise 5
Find the derivative of the expression.
- (5x + 6)5
Exercise 6
What's the derivative of the following expression?
- ln (x2 + x)