For the differential equation, find (a) one solution and then (b) all solutions.
y ' = 4x3
Answer
This looks like it came from using the power rule on the function
y = x4.
This is a solution. Since the derivative of a constant is zero, adding a constant to the function x4 doesn't change the derivative of that function. So we can write all solutions by
y = x4 + C
where C is any constant.
Example 2
For the differential equation, find (a) one solution and then (b) all solutions.
y' = x5
Answer
When we take the derivative of a polynomial the degree drops by 1, so this almost looks like it came from taking the derivative of the function y = x6. However, the derivative of x6 is 6x5. To cancel out the extra 6 we get when taking the derivative, we need to introduce a factor of . A solution to the differential equation could look like this:
All solutions look like this (for any constant C):
Example 3
For the differential equation, find (a) one solution and then (b) all solutions.
Answer
What is a function whose derivative is sin x? One answer is
y = -cos x
(take the derivative of -cos x if you need to convince yourself). To write all solutions, we write
y = -cos x + C
where C is any constant.
Example 4
For the differential equation, find (a) one solution and then (b) all solutions.
xy' = 4x
Answer
Divide both sides by x to get
y' = 4.
A solution is
y = 4x,
but all solutions can be written as
y = 4x + C
where C is any constant.
Example 5
For the differential equation, find (a) one solution and then (b) all solutions.
y" = -x-2
Answer
We need to think backwards twice. The first time, if we take the derivative of y' to get -x-2 we could have started with
Thinking backwards again, what function has as its derivative? This one:
y = ln x.
This is one solution. To find all solutions, start over. What has -x-2 as its derivative? Any function of the form
where B is any constant. In order to have such a y', we must have started with