We'll start off with Descartes' Rule of Signs. We have 2 sign changes in the original polynomial, so we have 2 or 0 positive real roots. f(-x) = -(-x)4 – 4(-x)3 + 14(-x)2 + 36(-x) – 45 = -x4 + 4x3 + 14x2 – 36x – 45 Again, we have 2 sign changes here, so we have either 2 or 0 negative real roots. The next step is the Rational Root Theorem, and it says that our possible rational roots are: ±1, ±3, ±5, ±9, ±15, ±45 Time for the dirty part of all this, digging for roots. Using our wonder shovel, synthetic division, on x = 1: We found one, and it's 1. Our quotient is -x3 – 5x2 + 9x + 45. How about some more synthetic division? Let's try x = -1. That's no root, it's a space station. No, wait, it isn't that either. It also isn't a lower bound; the signs in the quotient do not alternate. Let's go for another point, x = 3. Second root, unlocked. We are now down to a quadratic equation, -x2 – 8x – 15. We can factor this to -(x + 5)(x + 3) Now we can pull our entire polynomial into one big, fully factored mess: y = -(x – 1)(x – 3)(x + 3)(x + 5) We have found all four roots for our 4-degree polynomial. This is an even polynomial with a negative coefficient. We will wave our arms to floor like we just don't care. The multiplicity for every zero is 1, so they all cross over to the other side. |