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What do snickerdoodles and velocity have in common? Derivatives! No, that wasn't a bad attempt at a joke. Get on our level by watching this speedy...
AP Calculus 1.4 Derivatives. Which of the following best describes the quantity?
AP Calculus 1.4 Derivatives 202 Views
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AP Calculus 1.4 Derivatives. Which of the following best describes the quantity?
Transcript
- 00:00
Thank you We sneak all right Put this problem in
- 00:05
your calculator in shmoop All right Which of the following
- 00:08
best describes the quantity d y t ax given the
- 00:11
relation why cubed minus four x y squared plus eleven
- 00:14
x cubed equals seven and hear the potential All right
Full Transcript
- 00:19
thinking thinking we're doing okay They're asking us to find
- 00:24
the y d x which means this is a derivatives
- 00:27
problem to find the derivative of this relation we typically
- 00:30
right Why explicitly is a function of x so it
- 00:33
looks like why equals something But in this case it's
- 00:37
really hard to isolate Why So we can find the
- 00:39
derivative implicitly Instead this is called implicit differentiation shockingly which
- 00:46
basically means the dependent variable Why has not been written
- 00:50
explicitly in terms of the independent variable x So we
- 00:54
start by applying the derivative with respect to x to
- 00:57
each and every term in the equation Well the first
- 01:00
term is three y squared times d y t ax
- 01:03
because we're finding the derivative of ah wai term with
- 01:06
respect to x All right our second term is negative
- 01:09
for x times Why squared all for this term we
- 01:13
have to use the product rule because we have two
- 01:15
terms multiplied by each other Recalled that the product rule
- 01:18
tells us that the derivative of f of x times
- 01:22
g of ax equals f of x times the derivative
- 01:26
of g of x plus the derivative of f of
- 01:30
x times G of x we can pull out the
- 01:32
minus four as a constant and we'll get x times
- 01:36
two why the y d x plus y squared times
- 01:40
d x d acts which is just one So the
- 01:43
second term simplifies to negative eight X y c y
- 01:47
t ax minus for y squared All right Third term
- 01:51
eleven x cube becomes thirty three x squared We'd multiply
- 01:55
it by d x d x here too But that's
- 01:58
still just one and finally the derivative of seven or
- 02:01
any constant ever is just zero Now it can isolate
- 02:05
the righty axe and move the terms without d y
- 02:08
d x to the other side of the equation Well
- 02:10
the widely axe times three y squared minus eight x
- 02:13
y equals four y squared minus thirty three x squared
- 02:17
Then we just divide by three y squared minus eight
- 02:19
X y to get the idea ax equals four y
- 02:22
squared minus thirty three x squared all over three y
- 02:26
squared minus eight x Y look carefully at the answers
- 02:29
because they all look really similar He is Our answer 00:02:34.0 --> [endTime] is in the river No
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