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Description:

APCS: Standard Data Structures Drill 1, Problem 3. Which of the following is the best postcondition for the fillArray method?

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Transcript

00:00

Thank you We sneak and here's your shmoop too Sure

00:06

And by the way this week in history the first

00:08

software pirates sailed the high c plus plus is in

00:11

search of ruby and earl All our geeky coder friends

00:15

are really laughing at that one All right phil array

00:19

method has the following preconditions our is a valid in

00:23

terrain declared with a specified length greater than or equal

00:26

to one Are that bar well which of the following

00:32

is the best post condition for the pillory method And

00:35

here the potential answers we're thinking we're thinking and if

00:40

we stop now we're thinking again okay free and post

00:43

conditions are like promises we make to ourselves almost like

00:47

new year's resolutions except we actually wind up keeping In

00:51

the case of the phil ary method we're working with

00:53

the precondition that r is a valid array of imagers

00:57

with a length greater than or equal to one let's

01:00

walk through the method to see what it actually does

01:03

well first line hear gives us an imager named flynn

01:06

which is the length of the array we're going to

01:09

be filling The next line starts up for life the

01:12

three parameters were set up to create emitter i as

01:15

the counter starting at zero and specifies that lupul run

01:18

until ice less than len becomes false and iterated I

01:24

buy one each time The looks like the code within

01:27

the loop itself visits the array of whichever position i

01:30

is at the time and fills that position's content with

01:33

again number that eyes that though position zero in the

01:37

array will contain the number zero position four will contain

01:41

the number four and so on Get it let's Look

01:44

at the potential answers option a this one says that

01:47

our is an imager array of length twenty Well no

01:51

the hillary method is written in such a way that

01:54

it'll fill an array of whatever size we specified Option

01:57

b says our is an imager array of a length

02:00

thread a ventricle the one and each value equals its

02:03

index Hey that sounds exactly like what we're making better

02:07

check the other cells What option c says is technically

02:10

true but it's less specific than option b and that

02:12

it doesn't say anything about the values being the indices

02:16

though it's not our best choice option d again with

02:19

the twenty thing no option a is pretty similar to

02:22

be except that the arrays and unspecified size that's not

02:26

true erase sizes definitely greater than zero because the loops

02:29

generator starts at zero and aloof runs until the generator

02:33

is equal to or greater than our yeah software pirate

02:37

joke we've beaten to death If we specified we wanted

02:40

in a ray the sides of negative three for example

02:42

aside from being impossible the four loop wouldn't run it

02:45

all because the generator is already greater than our and

02:49

no array would be generated Not only that but our

02:51

precondition already specified The array of length is greater than

02:54

or equal to one so nuts to that Our answer's 00:02:57.115 --> [endTime] Definitely B no not r it's b

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