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Description:

AP Computer Science 1.5 Standard Data Structures. Which of the following is a correct iterative implementation?

Language:
English Language

Transcript

00:00

Thank you We sneak And here's your shmoop twos you're

00:05

brought to you by the power of two dirt bikes

00:10

now close All right which of the following is a

00:12

correct iterated implementations right here your potential answers And why

00:19

would i miss you Power raise candy bar Okay well

00:26

there are a number of ways to populate an array

00:29

and the two most obvious are sequential and iterated implementations

00:33

Well sequential is exactly as it sounds going right down

00:36

the line manually giving values to each array element one

00:39

by one that's what's happening in answer e And because

00:43

we're in the market for an illiterate of solution rather

00:45

than sequential we can throw e out right away because

00:49

the values we're going to be filling the array with

00:52

are all mathematically related powers of two which are practically

00:56

blood relatives or like a really close biker gang we

00:59

could pretty easily is an illiterate of implementation Here We'll

01:03

just need a simple loop that travels down the array

01:05

via its indices and at each stop multiplies have value

01:09

by two and copies that product to the array before

01:12

moving on Well let's see if any of the remaining

01:14

loops fit the bill Option a looks good Really good

01:18

Luke runs without errors but it doesn't do right in

01:21

terms of the problem given which is to fill the

01:24

array with the first ten powers of two starting with

01:26

two So this option starts with one instead All right

01:30

Well in fact he has the same problem By the

01:34

way b is an interesting luke but makes a textbook

01:36

mistake on the very first line It fails to take

01:39

into account the old array index begins at zero thing

01:43

The energy er i being used as an inter reiter

01:46

should started zero because in a raise indexing scheme starts

01:50

at zero not one run This bit of code and

01:53

index zero would get skipped over So no good but

01:56

just leave c which is our answer It heroically starts

01:59

it's iterated zero and the first value power at two

02:04

While eyes less than the total length of the array

02:06

it'll go through loop that changes the current array element

02:09

to the value of power Cia network Change the value

02:13

of power to be itself times two and increases the

02:16

value of the it aerator by one and that's the

02:18

whole hot well

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