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Statistics, Data, and Probability I Videos 30 videos
Statistics, Data, and Probability I: Drill Set 2, Problem 2. If this trend continues, what will be the price in week 7?
Statistics, Data, and Probability I: Drill Set 2, Problem 3. Which of the following statements is true?
Statistics, Data, and Probability I: Drill Set 2, Problem 4. Which of the following statements is true?
CAHSEE Math 1.4 Statistics, Data, and Probability I 200 Views
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Description:
Statistics, Data, and Probability I: Drill Set 1, Problem 4. How old was the final person to join?
- Statistics and Probability / Summarize, represent, and interpret data on a single variable
- Statistics and Probability / Summarize, represent, and interpret data on a single variable
- Statistics and Probability / Summarize, represent, and interpret data on a single variable
- Statistics and Probability / Summarize, represent, and interpret data on a single variable
- Statistics, Data Analysis, and Probability 6 / Statistical data
Transcript
- 00:03
Here's a boring shmoop-ily unvoiced question you'll find on the exam...
- 00:07
At a local high school, the mean age of its ten-member glee club is 16.
- 00:13
With the start of the new school year, the club is expecting the enrollment of
- 00:17
five additional new members, with the mean age of the first four new recruits as 14.
- 00:23
If the larger 15-member club turns out to have a mean age of 15.4,
Full Transcript
- 00:28
how old was the final person to join?
- 00:36
Here are the possible answers:
- 00:43
For this problem, we really have to know what mean... means.
- 00:47
Because it has nothing to do with that seriously unfriendly janitor,
- 00:50
Spyder, who works the night shift at your high school.
- 00:54
Mean just means... average.
- 00:55
Yep, we're dealing with an AVERAGING problem.
- 00:58
Remember Mrs. Slobovitz' words of wisdom:
- 01:01
Add up all the numbers, then divide by the number of items you added.
- 01:04
And get your feet off the desk.
- 01:06
So this question is asking for an average,
- 01:08
but there are really 2 parts to the... summing we'll have to do.
- 01:12
Yeah... we're gonna get sum.
- 01:15
The first part is the ten 16-year-old glee guys and gals.
- 01:19
16 times 10 is 160, which is how long they've all on this Earth, combined.
- 01:24
But that's only the first part. Now come the interlopers.
- 01:29
The second part tells us that 4 recruits have a mean age of 14.
- 01:33
Do you care if they were 10, 18, 6, and 22? Nah, not really.
- 01:38
We just want to solve the problem, we're not looking to start a Little League team.
- 01:42
We only care that the average age of those 4 recruits is 14.
- 01:47
So now we have 14 of the 15 already in the bag... age-wise...
- 01:51
...we know the numbers...
- 01:52
...so we'll be adding 10 times 16, or 160... to 4 times 14, or 56.
- 02:03
Just like the grocery story check out lady says, Your subtotal is 216, ma'am.
- 02:10
Only problem is that we're missing one body.
- 02:15
Let's just step back a sec for a reality check here.
- 02:18
What's our average up to this point? Well, we have 14 bodies and a total of 216...
- 02:23
so if we forgot about the last man standing, we could get the average age thus far if we wanted.
- 02:28
We have 216 divided by 14 which is 15.42... ish
- 02:32
That's an interesting number because they tell us that the overall average is 15.4.
- 02:40
Let's say we totally didn't get how to solve this problem. Like... no clue at all.
- 02:45
If we've got a calculator, the answer is at our fingertips.
- 02:48
Isn't it about time we gave up and let the machines win?
- 02:51
Let's look at the answer choices.
- 02:53
If the last one was 14, then we'd have:
- 02:55
216 + 14 = 230
- 02:58
Then we'd divide by 15 and get 15.33.
- 03:03
If the last one was 15 we'd have:
- 03:05
216+15 = 231
- 03:08
Then we'd divide by 15 and get 15.4. Hm...we'll come back to you, buddy...
- 03:13
If the last one was 16 we'd have:
- 03:15
216+16= 232
- 03:17
Then we'd divide by 15 and get 15.466.
- 03:22
If the last one was 17 we'd have:
- 03:23
216+17 = 233
- 03:26
Then we'd divide by 15 and get 15.533.
- 03:30
The formal name for this method of solving this kind of problem?
- 03:34
BRUTE FORCE.
- 03:35
And yeah - it's a tough way to make a living. This result leaves the age of the last recruit,
- 03:39
which we assume to be x.
- 03:41
The total sum of all 15 members' ages is 15.4 times 15 or 77 fifths times 15, which equals
- 03:51
231... so the equation in terms of the data sums is x + 160 + 56 = 231.
- 03:58
160 plus 56 is 216. If we subtract 216 from both sides, we're left with x on the left
- 04:04
side and 15 on the right side... so the age of the last member is 15.
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