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ACT Math Pre-Algebra: Drill 3, Problem 4. Find the solution to this equation.
CAHSEE Math 6.3 Algebra I 182 Views
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Description:
CAHSEE Math: Algebra I Drill 6, Problem 3. If x ounces of a 10% salt solution are added with 20 ounces of a 50% salt solution to create a combined 35% salt solution, what would be the value of x, or the amount of the 10% salt solution?
- Algebra / Create equations that describe numbers or relationships
- Algebra / Create equations that describe numbers or relationships
- Algebra / Create equations that describe numbers or relationships
- Algebra / Create equations that describe numbers or relationships
- Algebra / Create equations that describe numbers or relationships
- Algebra I / Solving multistep equations
Transcript
- 00:02
And here's another shmoop du jour.
- 00:04
If x ounces of a 10% salt solution…
- 00:06
…are added with 20 ounces of a 50% salt solution to create a combined 35% salt solution,
- 00:13
what would be the value of x, or the amount of the 10% salt solution?
- 00:18
And here are the potential answers…
Full Transcript
- 00:24
Basically, a highly diluted salt solution is being poured into a bucket with a more
- 00:27
concentrated solution…
- 00:29
…and the question wants to know how much we need of the highly diluted amount so that
- 00:33
the end result is a 35% salt solution.
- 00:37
So, said another way, x many ounces of the 10% diluted stuff is added to 20 ounces of
- 00:42
the 50% stuff; we want the total to be a 35% stuff.
- 00:47
The actual salt content of the 10% solution is 0.1x oz., while the salt content of the
- 00:55
50% solution is 0.5 times 20… or 10 oz.
- 00:59
These two amounts added together must equal the salt content in the combined solution.
- 01:04
So the combined equation looks like this:
- 01:06
0.1x plus 10 equals .35x plus .35 times 20.
- 01:12
If we simplify, we get .1x plus 10 equals .35x plus 7… which simplifies to 3 = .25x
- 01:22
Divide both sides by .25 and we get x equals 12.
- 01:25
So answer A is our guy.
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