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PSAT Math Diagnostic Videos 41 videos
PSAT 1.10 Math Diagnostic. Which of the following is a factor of the expression?
PSAT 1.3 Math Diagnostic. Which of the following most nearly represents the line of best fit?
PSAT 1.4 Math Diagnostic. Which of the following conclusions is supported by the data in the graph?
PSAT 1.14 Math Diagnostic 181 Views
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Description:
PSAT 1.14 Math Diagnostic. What value of b will make x have an imaginary component?
Transcript
- 00:00
Sorry And here's your shmoop du jour brought to you
- 00:05
by the square root sign Not surprisingly it's parents are
- 00:09
check mark and a horizontal line We're sure you can
- 00:11
see the resemblance All right if to x squared minus
- 00:15
b x equals negative nine what value of b will
Full Transcript
- 00:18
make x have an imaginary component And here the pencil
- 00:23
and imaginary well you may want to bring your imaginary
- 00:27
friend along for this one after all he's got credit
- 00:30
Okay We'll need to borrow the quadratic formula to solve
- 00:33
this baby So best to start by rearranging the equation
- 00:37
were given so it you know has that love and
- 00:40
feeling well that quadratic no way So we're going to
- 00:44
take to x squared minus b x equals negative nine
- 00:47
and add nine to both sides to get to x
- 00:49
squared minus b x plus nine equals zero they're quadratic
- 00:55
enough for you Okay now we need to find a
- 00:58
value for p when Acts as a non 0 imaginary
- 01:01
heart so let's use the discriminated shortcut he all that
- 01:05
good stuff under the square root sign in the quadratic
- 01:08
formula there b squared minus four a c ever plug
- 01:12
in a value for be here and you wind up
- 01:14
with a negative number Well then x has a non
- 01:17
zero imaginary part On the flip side of that coin
- 01:20
of your results is greater than or equal to zero
- 01:23
and the solution won't have an imaginary part Got it
- 01:26
It will be really sometimes to really plugging chuck time
- 01:30
The coefficient of our x squared term is to and
- 01:33
our last term is positive Nine so we get b
- 01:37
squared minus four times two times nine We'll set that
- 01:40
equal to zero four times two times nine is seventy
- 01:43
two so this simplifies to be squared minus seventy two
- 01:47
And then we add something to both sides Get b
- 01:49
squared equals seventy two and finally take the square root
- 01:53
of both sides Get that b is greater than or
- 01:55
equal to six square root of two Okay deep breath
- 02:01
Now as long as b is greater than or equal
- 02:04
to six square root of two x won't have an
- 02:07
imaginary heart However we're looking for the value that will
- 02:11
make x have an imaginary part And the only answer
- 02:15
choice that is smaller than six square root of two
- 02:17
is option A Where were the three but that's Our
- 02:20
answer course We believe that imaginary numbers should have all
- 02:23
the same rights and privileges as real numbers way Dont 00:02:26.99 --> [endTime] want to discriminate
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