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AP Physics 1 Videos 86 videos

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AP Physics 1: 3.1 System Interactions and Changes 198 Views


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AP Physics 1: 3.1 System Interactions and Changes. What is the coefficient of friction between the biscuit and the court?

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English Language

Transcript

00:00

Thank you We sneak and here's your shmoop too sure

00:05

brought to you by shuffleboard it's fun to play and

00:08

equally fun when older people call us the w word

00:12

whipper snapper all right shuffle boards a sport typically played

00:16

by retirees on cruise ships Grandpa shmoop stands at one

00:19

end of a narrow lane A grid with various scores

00:22

is located at the other end He uses a broom

00:25

to push a pot called a biscuit down the lane

00:28

If grandpa shmoop gives the four kilogram biscuit an initial

00:31

speed of five meters per second and the biscuit comes

00:35

to rest after ten meters what is the coefficient of

00:38

friction between the biscuit and the court And here the

00:41

potential answers All right well this could get complicated if

00:47

we let it The biscuit starts off with kinetic energy

00:51

and kinetic energy equals one half mass times velocity square

00:56

The coefficient of friction then goes to work on the

00:59

puck taking that kinetic energy away Well looks like this

01:03

is a job for the work energy the're Um the

01:06

work energy tour means that the work done by a

01:08

force becomes the kinetic energy of the object of forces

01:12

working on here's The equation In this case the biscuit

01:15

is losing energy so the changing kinetic energy is negative

01:20

and the work is negative as well So in our

01:25

question here the work done by friction is equal to

01:28

the change in kinetic energy Equation For the force of

01:31

kinetic friction is mass times gravity times that coefficient And

01:36

since we're working here we have to include displacement represented

01:40

by x Well now we can solve for the coefficient

01:43

you and we can see that as we solve this

01:46

equation we don't actually use the objects mass It cancels

01:49

itself out Coefficient mu equals velocity squared divided by two

01:55

tons Gravity times displacement So when we plug in those

01:59

numbers we get an answer of one eighth So option 00:02:02.49 --> [endTime] a Yeah that's it that's the correct answer

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