ShmoopTube

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Sorry And here's your shmoop du jour brought to you

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by people who can say the alphabet backwards either they're

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extremely smart they know how to reiterate backwards through an

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array or they've just done a lot of sobriety tests

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and you don't want to go there All right Which

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of the following implementation successfully copies over array my alf

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to a realist alphabet All right And here your potential

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answers brought to you by the romans Okay option one

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uses a for each loop which will cycle once for

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each element in an array In this case for each

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string in the array my alf we'll add the content

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of that element to the array list alphabet and the

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loop will in as soon as we've reached the end

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of my al that's about as simple as it gets

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and it will totally work all right Option two option

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two creates an iterated that begins at zero And while

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the current element of my health is not equal to

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z where it'll add that particular value to alphabet add

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one to the generator and do it all over again

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Do that to me one more time Great hold when

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the wild statement finally does find a value equal to

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z it'll end the loop and travel down to the

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next statement adding the current value of my alf meaning

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z we just found the alphabet so option two fits

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the bill to woo hoo wiseguys will have already noticed

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that none of the possible answers are all three options

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work and think we're totally done here but because we're

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also smart and uptight about things we're going to not

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just assume the answer is d all right so let's

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just check out option three and be sure it doesn't

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work looks decent on first glance right Well standard looking

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loop something niggling with the array list Nothing obviously a

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miss Ah wait we can't use that alphabet dot set

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call on indices that don't exist yet remember our ray

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list alphabet is totally empty all set replaces elements that

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already exist with other elements We need to use an

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ad call instead and if we're being nitpicky Well that

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four loop set up is saying well i is less

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than alphabet dot size and that would have to be

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changed to the size of alphabet at this stage would

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be zero so the loop would never run it all

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Changing that terminator parameter too While i is less than

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my health dot length would allow the loop to run

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the full twenty six Anyway we're done Wait okay we're 00:02:27.198 --> [endTime] leaving we're leaving

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