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AP Computer Science A Videos 108 videos

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AP Computer Science 3.2 Standard Data Structures 180 Views


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Description:

AP Computer Science 3.2 Standard Data Structures. Which of the following methods successfully add an element to the array?

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Transcript

00:00

Sorry And here's your shmoop du jour brought to you

00:05

by a ray list looking for an array You khun

00:08

dynamically resize it's a ray of hope want want which

00:13

of the following methods successfully add an element to an

00:15

array signs this crap over here that's Fine that code

00:19

Over here you looked in and here your potential answers

00:24

Okay here we go The purpose of this question seems

00:27

to remind us of the difference between a plane all

00:29

arrays and a ray lists they work the same way

00:32

in a lot of respects but one of the biggest

00:34

difference is the ability to dynamically resize array list While

00:38

old school razor stuck with the side they're given forever

00:42

this question featured in a ray list things would be

00:44

over with pretty quickly Add to an array list we

00:47

could just call the ad method toe add a value

00:49

to it whenever we'd like no sweat but this question

00:52

is asking us to do the impossible Add values to

00:55

a regular array can't be done unless we're a little

00:59

sneaky like option one so check this out option one

01:02

takes it upon itself to create a new array that's

01:05

one size larger Then it loops over the older ray

01:08

grabbing his values and adding them to the new array

01:11

once the loop finishes it adds the imager called lm

01:15

which would be the imager provided with the method call

01:17

to the end and returns the fresh new array very

01:21

slick option one could be a used car salesman option

01:24

Two seems simple enough thie idea seems to be to

01:26

place the contents of the imager elem at the index

01:30

corresponding to the total length of the array What this

01:33

method is attempting is almost clever if only it worked

01:37

Because all array indexes begin counting at zero the total

01:40

length of an array does not correspond directly to the

01:43

index values they're one off if you hadn't array with

01:46

the length of five which is to say five total

01:48

elements in it the array would be index from zero

01:51

to four if you had a twelve element array zero

01:54

to eleven and so on so this method is trying

01:56

to provide a value for an array member who's index

01:59

doesn't exist and will always be just one position out

02:03

of reach You know what that's like in life story

02:07

option two will keep throwing an array index out of

02:09

bounds exception until the end of time So totally not

02:12

gonna work and option three looks nice and simple That

02:15

ad function looks very handy except that yeah again this

02:19

isn't an array list ad calls like this one won't

02:23

do a single thing for our array here that makes

02:26

our answer A option One only like climbing over the

02:29

fence when the gate was wide open Option one made

02:31

it possible for us to do way more work than

02:34

necessary to achieve something that could have been done more 00:02:36.78 --> [endTime] easily Another way Well want want

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