Answer
Let's deconstruct this series. First, we can pull out a factor of 3 from each term to get
-3 + 3(0.1) – 3(0.01) + 3(0.001) – 3(.0001).
The things in the parentheses are are powers of .1, so write them that way:
-3(0.1)0 + 3(0.1)1 – 3(0.1)2 + 3(0.1)3 – 3(0.1)4
It makes sense to use n = 0 as the starting index, so to get the signs correct we need to have a factor of (-1)n + 1:
(-1)1 × 3(.1)0 + (-1)2 × 3(.1)1 + (-1)3 × 3(.1)2 + (-1)4 × 3(.1)3 + (-1)5 × 3(.1)4
Finally, we put things into sigma notation:
It would also make sense to start at n = 1, which is the exponent on the first factor of -1. Then the series looks like
(-1)1 × 3(0.1)0 + (-1)2 × 3(0.1)1 + (-1)3 × 3(0.1)2 + (-1)4 × 3(0.1)3 + (-1)5 × 3(0.1)4
and we would write it in sigma notation as